Solve 2x^2 + 3x - 7 = 0 using the quadratic formula.

For a quadratic equation ax^2 + bx + c = 0, use the quadratic formula:
x = (-b ± sqrt(b^2 - 4ac))/(2a)

For 2x^2 + 3x - 7 = 0:
a = 2
b = 3
c = -7

Substitute these values into the formula:
x = (-3 ± sqrt(3^2 - 4(2)(-7)))/(2(2))

Simplify the discriminant:
3^2 - 4(2)(-7) = 9 + 56 = 65

Therefore:
x = (-3 ± sqrt(65))/4

Since 65 has no perfect-square factor greater than 1, this is already in simplest exact form.