Find the indefinite integral ∫(6x^2 - 4x + 5) dx.

Solution

Calculus · Easy

Step 1: Integrate each term separately.

We need to evaluate:
∫(6x^2 - 4x + 5) dx

Use the power rule for integration:
∫x^n dx = x^(n+1)/(n+1) + C, for n ≠ -1

Step 2: Integrate 6x^2.

∫6x^2 dx = 6(x^3/3)

Simplify:
6(x^3/3) = 2x^3

Step 3: Integrate -4x.

∫-4x dx = -4(x^2/2)

Simplify:
-4(x^2/2) = -2x^2

Step 4: Integrate 5.

∫5 dx = 5x

Step 5: Combine the results and include the constant of integration.

∫(6x^2 - 4x + 5) dx = 2x^3 - 2x^2 + 5x + C

The constant C is necessary because differentiating any constant gives zero.

Therefore, the indefinite integral is 2x^3 - 2x^2 + 5x + C.

Result

2x^3 - 2x^2 + 5x + C