Find the distance between the points (-2, 3) and (4, 11) on the coordinate plane.

Solution

Geometry · Medium

Use the distance formula:
d = √((x2 - x1)^2 + (y2 - y1)^2)

The points are (-2, 3) and (4, 11).

Substitute the coordinates:
d = √((4 - (-2))^2 + (11 - 3)^2)

Simplify the differences:
d = √(6^2 + 8^2)

d = √(36 + 64)

d = √100

d = 10

Therefore, the distance between the two points is 10 units.

Result

10 units